At 10 a.m. two trains started travelling toward each other from stations 287 miles apart. They passed each other at 1:30 pm the same day. They average speed of the faster train exceeded the average speed of the slower train by 6 miles per hour. which of the following represents the speed of the faster train, in miles per hour?
Created: 6 years ago |
Updated: 2 years ago
best des
Let the average speed of slower and faster trains be S and (S + 6) miles/hr respectively.
Time taken = 10 am to 1:30 pm = 3.5 hr
Distance travelled by slower train = 3.5S
Distance travelled by faster train = 3.5(S + 6)
Now, 3.5S + 3.5(S + 6) = 287
or, 3.5S + 3.5S + 21 = 287
or, 7S = 287 - 21
or, 7S = 266
or, S = 266/7 = 38 miles/hr
So, speed of the faster train, S + 6 = 38 + 6 = 44 miles/hr
Md Azizur Rahman
Founder of Satt
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